Found highest pandigital concat product

38/main.py

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+'''
+Take the number 192 and multiply it by each of 1, 2, and 3:
+
+192 × 1 = 192
+192 × 2 = 384
+192 × 3 = 576
+By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
+
+The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
+
+What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?
+'''
+
+def conLength(n):
+    i = 1
+    p = len(str(n))
+    while p < 9:
+        i += 1
+        p += len(str(i * n))
+    
+    if p == 9:
+        return True
+    
+    return False
+
+def isPandigital(n):
+    digits = {1, 2, 3, 4, 5, 6, 7, 8, 9}
+    if set(map(int, str(n))) == digits:
+        return True
+    return False
+
+def concatProduct(n):
+    i = 1
+    d = n
+
+    while len(str(d)) < 9:
+        i += 1
+        d = int(str(d) + str(n * i))
+    
+    return d
+
+def main():
+    print("Hello this is Patrick")
+
+    m = 0
+
+    for i in range(1, 54321):
+        if conLength(i):
+            d = concatProduct(i)
+
+            if isPandigital(d) and d > m:
+                m = d
+    
+    print(m)
+
+if __name__ == "__main__":
+    main()