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'''
The arithmetic sequence, 1487, 4817, 8147, in which each of the terms increases by 3330, is unusual in two ways: (i) each of the three terms are prime, and, (ii) each of the 4-digit numbers are permutations of one another.
There are no arithmetic sequences made up of three 1-, 2-, or 3-digit primes, exhibiting this property, but there is one other 4-digit increasing sequence.
What 12-digit number do you form by concatenating the three terms in this sequence?
'''
import math
import numpy as np
from itertools import permutations
def sieve(n):
assert n > 1
ns = [True] * n
for i in range(2, math.ceil(np.sqrt(n))):
if ns[i]:
j = pow(i, 2)
while j < n:
ns[j] = False
j = j + i
return [i for i,val in enumerate(ns) if val][2:]
def digitToList(n):
return [int(c) for c in str(n)]
def listToDigit(l):
res = 0
for i in l:
res = 10 * res + i
return res
def main():
print("Hello this is Patrick")
primeSet = set(sieve(10000)) - set(sieve(1000))
primeList = list(primeSet)
for p in primeList:
perms = list(set(map(listToDigit, list(permutations(digitToList(p))))))
for perm in perms:
if p != perm and perm in primeSet:
if max(p, perm) + abs(p - perm) in primeSet and max(p, perm) + abs(p - perm) in perms:
print(min(p, perm), max(p, perm), max(p, perm) + abs(p - perm))
if __name__ == "__main__":
main()