Easy bruteforce solution

30/main.py

@@ -0,0 +1,26 @@
+# Digit fifth powers
+
+# 1634, 8208 and 9474 are the only number that can be written as the sum of the fourth powers of their digits
+# Find the sum of all the numbers that can be written as the sum of the fifth powers of their digits
+
+# Through some googling, we found an upper bound of the result at 6*9^5 = 354294
+# So, we can just bruteforce it, not that big of a search space
+
+def intToList(n):
+	return [int(d) for d in str(n)]
+
+def sumIntPowers(n, p=5):
+	return sum([d**p for d in intToList(n)])
+
+def main():
+	print("Hello, this is Patrick")
+
+	result = 0
+	for n in range(10, 999999):
+		if n == sumIntPowers(n):
+			result += n
+
+	print(result)
+
+if __name__ == "__main__":
+	main()