First try with Jenkinsfile, hope for the best

Jenkinsfile

@@ -0,0 +1,18 @@
+pipeline {
+    agent linux {
+        stages {
+            stage('Build') {
+                steps {
+                    echo 'Starting build step...'
+                    sh './scripts/build.sh'
+                }
+            }
+
+            // Testing latex isn't really a thing, but we could do basic sanity checks in the future?
+
+            stage('Deploy') {
+                echo 'Starting deploy step...'
+            }
+        }
+    }
+}

assignments/main_text.tex

@@ -17,4 +17,6 @@
 \subfile{week2/main.tex}
 \clearpage
 \subfile{week3/main.tex}
+\clearpage
+\subfile{week4/main.tex}
 \end{document}

assignments/week4/main.tex

@@ -0,0 +1,59 @@
+\documentclass[../main_text.tex]{subfiles}
+\begin{document}
+\setcounter{exercise}{0}
+
+\part{Assignment 4}
+
+\exercise*
+\begin{tcolorbox}
+    We say a set $F \subset \R$ is \textit{closed} if its complement $F^c := \R \backslash F$ is open. Since
+    $\emptyset$ and $\R$ are open, it follows that $\emptyset$ and $\R$ are closed as well.
+
+    \begin{enumerate}[label=\emph{(\alph*)}]
+        \item Let $a,b \in \R$ with $a < b$. Prove that $[a,b]$ is closed.
+        \item Is the set $\Z \subset \R$ closed? Provide a proof to substantiate your claim.
+        \item Is the set of rationals $\Q \subset \R$ closed? Provide a proof to substantiate your claim.
+    \end{enumerate}
+\end{tcolorbox}
+
+\begin{enumerate}[label=\emph{(\alph*)}]
+    \item The complement of $[a,b]$ is equal to the union of $(-\infty, a)$ and $(b, \infty)$. So, we have to prove
+        that both these sets are open. But we have already done so in the assignment of the previous week, so I'll just
+        leave it at that.
+    \item To prove that $\Z \subset \R$ is closed, we have to prove that the complement is open. Since the complement
+        consists of the union of a countably infinite number of open intervals $(a, b)$ such that $a < b$, we know
+        from a combination of earlier exercises that this is the case. This is because any interval $(a, b)$ is open
+        if $a,b \in \R$ such that $a < b$ and for any two open interval $A$ and $B$ that are open, then $A \cup B$
+        is open as well.
+    \item I claim that the set of rationals isn't closed in $\R$. This is because there doesn't exist any interval
+        $(a,b)$ where $a,b \in \Q$ such that $a < b$, since for any $a$ and $b$ you can always find a $c$ such that
+        $a < c < b$. This makes it impossible to find an $\epsilon > 0$ such that for any $x \in (a,b)$,
+        $(x - \epsilon, x + \epsilon)$ is also in $(a,b)$ but in such a way that it only contains irrational numbers.
+        This argument makes use of the fact that $\Q$ is dense in $\R$.
+\end{enumerate}
+
+\exercise*
+\begin{tcolorbox}
+    \begin{enumerate}[label=\emph{(\alph*)}]
+        \item Let $\Lambda$ be a set (not necessarily a subset of $\R$), and for each $\lambda \in \Lambda$, let
+            $F_\lambda \in \R$. Prove that if $F_\lambda$ is closed for all $\lambda \in \Lambda$ then the set
+            \begin{equation*}
+                \bigcap_{\lambda \in \Lambda} F_\lambda = \{x \in \R : x \in F_\lambda \text{ for all }
+                \lambda \in \Lambda\}
+            \end{equation*}
+            is closed.
+        \item Let $n \in \N$, and let $F_1,...,F_n \subset \R$. Prove that if $F_1,...,F_n$ are closed then the set
+            $\bigcup_{m=1}^n F_m$ is closed.
+    \end{enumerate}
+\end{tcolorbox}
+
+This exercise is very similar to an exercise of the previous assignment, in which we looked at unions and intersections
+of \textit{open} intervals, whereas in this exercise, it's all about closed intervals. As the definition of closed
+intervals is intricately linked to the definition of open intervals, the following arguments will look very similar and
+shouldn't be surprising.
+\begin{enumerate}[label=\emph{(\alph*)}]
+    \item
+    \item
+\end{enumerate}
+
+\end{document}

scripts/build.sh

@@ -0,0 +1,32 @@
+#!/bin/bash
+
+# Check if necessary packages are installed
+necessary_packages=("pdflatex")
+
+for package in ${necessary_packages}; do
+    if ! [dpkg -l ${package} > /dev/null]; then
+        echo "Error: ${package} is not installed."
+        exit 1
+    fi
+done
+
+# Build all directories
+subdirectory_file_name=main
+
+for D in *; do
+    if [ -d "${D}" ]; then
+        echo "Building ${D}..."
+        cd ${D}
+        pdflatex -interaction=nonstopmode -halt-on-error ${subdirectory_file_name}.tex
+        cd ..
+    fi
+done
+
+# Build main PDF
+main_file_name=main_text
+
+echo "Building main PDF..."
+pdflatex -interaction=nonstopmode -halt-on-error ${main_file_name}.tex
+
+# Clean up
+rm -rf *.aux *.log *.out *.toc